Answer:
Here are the choices
The strength of a correlation is independent of whether the correlation of a scatterplot is positive or negative. A scatterplot with positive correlation can have either weak correlation or strong correlation.
The slope of a line is independent of whether the correlation of a scatterplot has positive or negative correlation. A scatterplot with a negative slope can have either positive correlation or negative correlation.
The nonlinear association of a scatterplot depends on whether it has a weak or strong correlation. A scatterplot with nonlinear association will have a strong correlation.
The nonlinear association of a scatterplot depends on whether it has a positive or negative correlation. A scatterplot with nonlinear correlation will have a negative correlation.
It's a, because if it is positive, it can either be one skinny line, or one thick fat confusing line. Positive isn't perfect.
Answer came from duboistristan
Answer:
Step-by-step explanation:
Given that the number of asthma sufferers in the world was about 84 million in 1990 and 130 million in 2001.
Let N represent the number of asthma sufferers (in millions) worldwide t years after 1990.
a) If linear function let us assume 1990 as base year 0 then 2001 would be year 11
When written as ordered pairs year and asthma sufferers in millions we have
(0,84) and (11,130) lie on the line
Using two point formula equation of line is
Slope = 46/11
b) When exponential we have
![N =84e^{kt}](https://tex.z-dn.net/?f=N%20%3D84e%5E%7Bkt%7D)
Use N(11) = ![84e^{11k}=130\\k=0.0397](https://tex.z-dn.net/?f=84e%5E%7B11k%7D%3D130%5C%5Ck%3D0.0397)
![N =84e^{0.0397t}](https://tex.z-dn.net/?f=N%20%3D84e%5E%7B0.0397t%7D)
c) In 2010, t = 20
Linear y(20) = ![\frac{46*20}{11} +84\\=167.64](https://tex.z-dn.net/?f=%5Cfrac%7B46%2A20%7D%7B11%7D%20%2B84%5C%5C%3D167.64)
When exponential
N(20) = ![84e^{0.0397*20}\\=185.81](https://tex.z-dn.net/?f=84e%5E%7B0.0397%2A20%7D%5C%5C%3D185.81)
Answer: i
Step-by-step explanation:
i2 = −1i3 = i2 x i = −1 x i = −ii4 = i2 x i2 = −1 x −1 = 1Hence, i233 =i4 x 58 + 1 = i232 x i1 = 1 x i = i
It’s standard form
standard form is generally ax^2+bx+c
<span>8.5k+7-7.5k=9
first combine like terms </span>8.5k and -7.5k to get 1k or just k
k+7=9
subtract 7 from both sides to isolate k
k = 2