The answer is C
Commutative Property of Addition
Answer:
The probability that none of these taxpayers will be audited by the IRS is 0.8996 or 89.36%
Step-by-step explanation:
According to given:
Probability of being audited for income less than $50,000 = 6/1000 = 0.006
Therefore,
Probability of not being audited for income less than $50,000 = 1 - 0.006 = 0.994
Similary,
Probability of being audited for income more than $100,000 = 49/1000 = 0.049
Therefore,
Probability of not being audited for income more than $100,000 = 1 - 0.049 = 0.951
Now, for the probability of 2 persons with less $50,000 income and 2 persons with more than $100,000 income, to not being audited, we must multiply the probabilities of not being audited of each of the 4 persons.
Therefore,
Probability that none of them is audited = (0.994)(0.994)(0.951)(0.951)
<u>Probability that none of them is audited = 0.8936 = 89.36%</u>
Answer:
B
Step-by-step explanation:
C = R/1.8 - 273
C + 273 = R/1.8
1.8 * (C + 273) = R
1.8 can also be read as the fraction 9/5.
9/5 * (C + 273) = R
Thus your answer is B. Hope I helped!
Hello! I can help you! In general, the larger the size, the larger the cost. We will assume that $8 is the youth size and $12 is the adult size. x is the youth side and y is the adult side. The first part of the equation is 8x + 12y, BUT the key words in the problem are AT MOST, so out sign will be less than or equal to (≤), because the number can't be higher than 216, but it could be right at that number or less, so the equation is 8x + 12y ≤ 216. The answer is A.
Answer: Choice A) mean, there are no outliers
Have a look at the image attached below. I made two dotplots for the data points. The blue points represent bakery A. The red points represent bakery B. For any bakery, the points are fairly close together. There is no point that is off on its own. So there are no outliers, making the mean a good choice for the center. If there were outliers, then the median is a better choice. The mean is greatly affected by outliers, while the median is not.
