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Musya8 [376]
3 years ago
11

Help me pleaseeeee!! <3

Mathematics
1 answer:
nignag [31]3 years ago
3 0
I’m pretty sure the answer is 11 1/3
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Answer:

\frac{dN}{dt} = λN           N(0) = 6

N(t) = N₀e^(λt)

Applying the inital value condition

N(t) = 6e^(λt)

Step-by-step explanation:

Summarizing  the information briefly and stating the  variables in the problem.

t = time elapsed during the decay

N(t) = the amount of the radioactive substance remaining after time t

λ= The constant of proportionality  is called the decay constant or decay rate

Given the initial conditions

N(0) = N₀ = 6

The rate at which a quantity of a radioactive substance decays (\frac{dN}{dt}) is proportional to the quantity of the substance (N)  and λ is the constant of proportionality  is called the decay constant or decay rate :

\frac{dN}{dt} = λN          

N(t) = N₀e^(λt) ......equ 1

substituting the value of  N₀ = 6 into equation 1

N(t) = 6e^(λt)

3 0
3 years ago
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