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3 years ago

A shopper bought shoes marked $40. The sales tax is 8%. How much did the shopper pay in all?

Mathematics

2 answers:

anastassius [24]3 years ago

6 0

Answer:

follow step by step to get answer

Step-by-step explanation:

take 40 and multiply it by 0.08 then add that number to 40 and you get your answer.

Sauron [17]3 years ago

3 0

Answer:

40/100*8 = 3.2 (tax) 40+3.2 = $43.20

Step-by-step explanation:

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7t+3=8+7t<br><br> Thanks For The Help!

frutty [35]

Answer:

infinite

Step-by-step explanation:

1/6 of 12 is 2

1/6 of 18 is 3

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2z-3=2z-3

meaning you can put literally any number in place of z and it'd work.

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3 years ago

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What is the prime factorization of 48

irina1246 [14]

2*2*2*2*3, it's all the prime numbers that make 48 when multiplied together

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3 years ago

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Question 2(Multiple Choice Worth 1 points) (06.01) Solve 2x + 5y = −13 3x − 4y = −8 (4, 1) (−4, 1) (4, −1) (−4, −1)

dlinn [17]

ANSWER

The solution is
$(-4,-1)$

EXPLANATION

The given equations are:

$2x + 5y = - 13...(1)$

and

$3x - 4y = - 8...(2)$

We multiply equation 1 by 3 to get,

$6x + 15y = - 39...(3)$

We multiply equation 2 also by 2 to get,

$6x - 8y = - 16...(4)$

We subtract equation 4 from equation 3 to get,

$23y = - 23$
This implies that,

$y = - 1$

We put this value of y into any of the equations say equation 2

$3x - 4( - 1) = - 8$
Simplify

$3x + 4 = - 8$
Group like terms
$3x = - 8 - 4$
Simplify,

$3x = - 12$

Divide both sides by 3 to get,

$x = - 4$

Therefore the solution is
$(-4,-1)$

The correct answer is option D.

3 0

4 years ago

An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th

Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

3 0

3 years ago

How do you solve 10+5(3x-4)=2x+7

Taya2010 [7]

Answer: