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3 years ago

Given f(x)=5x-4, solve for x when f(x)=1

Mathematics

1 answer:

Sergio [31]3 years ago

8 0

Answer:

X=1

Step-by-step explanation:

1=5x-4

5=5x

5/5=5/5x

X=1

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kotegsom [21]

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3 years ago

Read 2 more answers

NEED HELP IMMEDIATELY Which expression is equivalent to one over four n − 16? a. one over four(n − 4)

erica [24]

A because just multiply 1/4 by 16 and u get 4

8 0

3 years ago

Solve the system of linear equations below.<br><br> y = -2x + 19<br> y = x + 7

ASHA 777 [7]

Hey there!

y = -2x + 19
y = x + 7

We gonna solve this system of equation by using the substitution method.

We wanna solve y = -2x + 19 for y

Let start by substitute -2x + 19 for y in y = x + 7

y = x + 7
-2x + 19 = x + 7

Subtract x from both sides

-2x + 19 - x = x + 7 - x

-3x + 19 = 7

Now subtract 19 on both sides

-3x + 19 - 19 = 7 - 19

-3x = -12

Then divide both sides by -3

-3x/-3 = -12/-3

x = 4

We have the value of x. Now we gonna use that same value to find the value for y.

We gonna do that by substitute 4 for x in y = -2x + 19

y = -2x + 19

y = -2(4) + 19

y = -8 + 19

y = 11

Thus,

The answer is: x = 4 and y = 11

Let me know if you have questions about the answer. As always, it is my pleasure to help students like you!

6 0

3 years ago

At the beginning of a 10-hour experiment,a substance has an initial temperature of 19.7 degrees C. The substance is cooled at a

Olin [163]

Answer:

-6.3

Step-by-step explanation:

2.6 * 10 (10 hours and 2.6 degrees) = 26

19.7 - 26 = -6.3

3 0

3 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$