Step-by-step explanation:
csc θ sin θ
(1 / sin θ) sin θ
1
1) marbles altogether = 3+4=7
P(black) = 3/7
2) P(first black marble)= 3/7
second black marble - When you removed 1st one only 2 black marbles are left and altogether marbles that are left = 6
P(second black marble) = 2/6=1/3
P(2 black marbles without replacement) means black and black marbles without replacement.
P(2 black marbles without replacement) =3/7*1/3=1/7
3) P(first black marble)= 3/7
When you put that black marble back, you got again <span>3 black marbles and 4 red marbles in a bag. So,
</span> P(second black marble)= 3/7
P(2 black marbles with replacement)=3/7*3/7= 9/49<span>
</span>
Answer:

Step-by-step explanation:

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Answer:
c = 8
Step-by-step explanation:
Use synthetic division here; it's the fastest approach.
Given that (x + 2) is a factor, take -2 and use this as the divisor in synthetic division:
-2 4 c 1 2
-8 (-2c+ 16) (4c-34)
---------------------------------------------
4 (c - 8) (-2c + 17) 4c - 32
The remainder, 4c - 32, must equal zero if (x + 2) is a factor.
Then 4c - 32 = 0, and c = 8
Round 3308.89 to the nearest Australian dollar - $4336 AUD .