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dem82 [27]
3 years ago
14

Santosh spent $200, before tax, on a DVD player and DVDs. The player cost $120, new DVDs cost $15 and used DVDs cost $5. Santosh

purchased the same number of new and uses DVDs. Write and solve an equation to find the number of each type of DVD Santosh purchased.
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

Santosh purchased 4 new and 4 used DVDs.

Step-by-step explanation:

From the information given, as you know that Santosh spent $200 and that the DVD player cost $120, you can say that the new and used DVDs cost $80, which can be expressed as:

15x+5y=80, where:

x refers to the number of new DVDs

y refers to the number of used DVDs

Now, as the statement indicates that Santosh purchased the same number of new and used DVDs, this means that x is equal to y and you can replace y with x and solve for x:

15x+5x=80

20x=80

x=80/20

x=4

According to this, the answer is that Santosh purchased 4 new and 4 used DVDs.

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Answer:

1) (-50) <(-25) < (-10) < 10 < 25

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Step-by-step explanation:

For the first question we list the numbers according to their sign(start from negative)

For the second question we multiply height with width to find the area of the rectangle.

8 0
3 years ago
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In 687,332,195, how is the value of the three in the ten thousands place related to the value of the 3 in the hundred thousands
olganol [36]
<span>In this case, the value of the first 3 (the ten-thousands) has a value of 30,000. The 3 next to it, in the hundred-thousands place, has a value of 300,000. To compare the two, the 3 on the right has a value one-tenth as much as that on the left.</span>
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3 years ago
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Factorise this expression as fully as possible 14t^3 x 6t
kupik [55]
14t^3*6t
= (14*6)*(t^3*t)
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6 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
A company paid $72 for 2 cases of printer paper each case contained 12 packages of paper next month the company's office manager
Tems11 [23]
To figure out the cost for 180 packages, you must first calculate how many packages they bought for $72. Since each case holds 12 packages, for $72, the company bought 24 packages (12×2). Then you have to divide 24 into 180 to figure out the cost for those 180 packages and get 7.5. To get the cost of the 180 packages, you must multiply 7.5 (the number of 24 packages that go into 180) by 72 (the cost of one group of 24 packages). You then get 540. The company must pay $540 for the 180 packages.
7 0
3 years ago
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