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3 years ago

How to solve and and correct answer please !!!!!!! Highly appreciate the help

Mathematics

1 answer:

sergey [27]3 years ago

8 0

12 /4 st your answer would be 3 st

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I don't really know how to do this can someone help

crimeas [40]

Step-by-step explanation:

Add them all up and subtract from 360.

Answer: 71

I think this is right

hope this helps :)

4 0

3 years ago

Help please

tester [92]

Answer:

64y² - 81

Step-by-step explanation:

(8y +9)(8y - 9)

64y² - 72y + 72y - 81

64y² - 81

6 0

3 years ago

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Minchanka [31]

Answer:

$1,165\frac{1}{3}\ yd$

Step-by-step explanation:

In this problem we have a regular octagonal barrier (That means that all the length side are equal)

Find out the perimeter of the barrier

The perimeter is equal to

$P=8b$

where

b is the length side of the barrier

we have

$b=145\frac{2}{3}\ yd= 145+\frac{2}{3}=\frac{437}{3}\ yd$

substitute in the formula of perimeter

$P=8(\frac{437}{3})=\frac{3,496}{3}\ yd$

Convert to mixed number

$\frac{3,496}{3}\ yd=\frac{3,495}{3}+\frac{1}{3}=1,165\frac{1}{3}\ yd$

3 0

3 years ago

Which of the equations are true identities? a. (3x-2y)(2y-3x)=9x^2-4y^2 b. (2k+5r)(2k-5r)=4k^2-25r^2

krok68 [10]

Answer:

b. $(2k+5r)(2k-5r)$

Step-by-step explanation:

We have to find the equation which are true identity.

a. $(3-2y)(2y-3x)$

$(3x-2y)(2y-3x)=3x(2y-3x)-2y(2y-3x)$

$=6xy-9x^2-4y^2+6xy$

$(3-2y)(2y-3x)\neq 9x^2-4y^2$

b. $(2k+5r)(2k-5r)$

$(2k)^2-(5r)^2$

Using identity

$(a+b)(a-b)=a^2-b^2$

$4k^2-25r^2$

It is true.

Hence, option b is true.

7 0

3 years ago

Complete the magic square using nos 1 to 15 without repeating the nos so that the sum of each row, diagonal, and column is 30.

scZoUnD [109]

Answer:

refer the attachment......

Step-by-step explanation:

hope this works

7 0

3 years ago

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