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3 years ago

Triple number multiplication

2 answers:

8 0

If your wondering how to do triple number multiplication then
If you have three numbers like 2x3x4 you'd multiply 2x3=6 then you'd multiply 6x4 and get 24... If you need to know something else I need more info.

tamaranim1 [39]3 years ago

4 0

Do you need me to explain this can u be a little bit more specific?

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This is due in 15 minutes pls help me lol thx

GaryK [48]

Answer:

ITS A

Step-by-step explanation:

PLZ GIVE BRAINLEIST

7 0

3 years ago

Read 2 more answers

Help me pleaseeee due in one minute

r-ruslan [8.4K]

Answer:

The anwer is 1/2

$P=N_Y/Total=3/6=1/2$

8 0

4 years ago

Since all squares are similar, then the ratio of one square’s side to perimeter is proportional to any other’s. If the side of a

kotegsom [21]

The perimeter is 36 yd.

We set up a proportion to represent this situation. We know that the ratio of the side to the perimeter is the same for every square. This means that the ratio of the first square, 2/8 is the same for the second one. We know that the side length is 9, which gives us:

2/8 = 9/x

Cross multiply:
2*x = 8*9
2x = 72

Divide both sides by 2:
2x/2 = 72/2
x = 36

5 0

3 years ago

Read 2 more answers

Whats 63/100-5/10? with an good 5th grade explanation

Ilia_Sergeevich [38]

Answer: .13

Step-by-step explanation:

63/100=0.63

5/10=0.50

=.13

I took 63 and divided it by 100 to get .63 and took 5 and divided it by 10 to get .50 so I took them and subtracted them to get .13

4 0

3 years ago

You are running a race. The probability that you win is 3/5. What is the probability that you lose at most 2 out of your 6 races

Veronika [31]

Answer:

The probability that you lose at most 2 out of your 6 races is 0.54432.

Step-by-step explanation:

We are given that you are running a race. The probability that you win is 3/5.

There are total of 6 races.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 6 races

r = number of success = at most 2 lost

p = probability of success which in our question is probability that

you lose a race = 1 - (3/5) = 2/5 or 0.4

Let X = Number of races lost

So, X ~ Binom(n = 6, p = 0.40)

Now, the probability that you lose at most 2 out of your 6 races is given by = P(X $\leq$ 2)

P(X $\leq$ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= $\binom{6}{0} \times 0.40^{0} \times (1-0.40)^{6-0} + \binom{6}{1} \times 0.40^{1} \times (1-0.40)^{6-1} + \binom{6}{2} \times 0.40^{2} \times (1-0.40)^{6-2}$

= $1 \times1 \times 0.60^{6} + 6 \times 0.40^{1} \times 0.60^{5} +15\times 0.40^{2} \times 0.60^{4}$

= 0.54432

7 0

3 years ago