Step-by-step explanation:
The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segment BQ is perpendicular to AC, find the magnitude of ABC
<1 = 120/2 = 60
answer
60 <span>degrees</span>
Answer:
The length of the line segment UV is 76 units
Step-by-step explanation:
In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length
In Δ ONT
∵ U is the mid-point of ON
∵ V is the mid-point of TN
→ That means UV is joining the mid-points of two sides
∴ UV // OT
∴ UV = 
OT
∵ UV = 7x - 8
∵ OT = 12x + 8
∴ 7x - 8 = (12x + 8)
→ Multiply the bracket by
∵ (12x + 8) = (12x) + (8) = 6x + 4
∴ 7x - 8 = 6x + 4
→ Add 8 to both sides
∴ 7x - 8 + 8 = 6x + 4 + 8
∴ 7x = 6x + 12
→ Subtract 6x from both sides
∴ 7x - 6x = 6x - 6x + 12
∴ x = 12
→ Substitute the value of x in the expression of UV to find it
∵ UV = 7(12) - 8 = 84 - 8
∴ UV = 76
∴ The length of the line segment UV is 76 units
Answer:
$392
Step-by-step explanation:
5.6% of $7000 is 392
Answer:
The probability that a household has at least one of these appliances is 0.95
Step-by-step explanation:
Percentage of households having radios P(R) = 75% = 0.75
Percentage of households having electric irons P(I) = 65% = 0.65
Percentage of households having electric toasters P(T) = 55% = 0.55
Percentage of household having iron and radio P(I∩R) = 50% = 0.5
Percentage of household having radios and toasters P(R∩T) = 40% = 0.40
Percentage of household having iron and toasters P(I∩T) = 30% = 0.30
Percentage of household having all three P(I∩R∩T) = 20% = 0.20
Probability of households having at least one of the appliance can be calculated using the rule:
P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)
P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20 P(at least one of the three) = 0.95
The probability that a household has at least one of these appliances is 0.95
