Hey there :)
3 ( 2t + 1 )
We use what is called the distributive property to get rid of the parenthesis
We multiply the term outside the parenthesis by all terms inside
3 ( 2t ) + 3 ( 1 )
6t + 3 → Your answer
QUESTION 1
The given logarithmic expression is
We rewrite 
in the index form to base 4.
This implies that;
We now apply the power rule: 
.
Recall that logarithm of the base is 1.
QUESTION 2
The given logarithm is;
![\log_2(\sqrt[5]{32})](https://tex.z-dn.net/?f=%5Clog_2%28%5Csqrt%5B5%5D%7B32%7D%29)
![\log_2(\sqrt[5]{2^5})](https://tex.z-dn.net/?f=%5Clog_2%28%5Csqrt%5B5%5D%7B2%5E5%7D%29)
This is the same as;
The coordinates of the fourth corner is
A. (-1, 3)
Using the cosine ratio, the value of AD in the diagram is: 2√3π in.
<h3>How to Apply the Cosine Ratio?</h3>
If we have the following given in a right triangle like triangle ADC in the diagram:
AC = 4π (hypotenuse)
AD = ? (adjacent side)
The cosine ratio, CAH would be applied, which is:
Cos 30 = adjacent/hypotenuse
Cos 30 = AD/4π
AD = cos 30 × 4π = √3/2 × 4π [cos 30 = √3/2]
AD = 2√3π in.
Learn more about the cosine ratio on:
brainly.com/question/15793827
#SPJ1
