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rodikova [14]
3 years ago
15

How much will $1000 deposited in an account earning 7% interest compounded annually be worth in 20 years? (which formula do I us

e? I am confused...txs)
Mathematics
1 answer:
Xelga [282]3 years ago
5 0

Answer:

$3870

Step-by-step explanation:

Hello, the initial deposit is $1000.

After one year, we will get 1000 + 7%*1000= 1000 * ( 1+7%) = 1000 * (1+0.07)

= 1000 * 1.07

And we want to compound it so the second year we will get

1000 * 1.07 * 1.07 = 1000 * 1.07^2

And after n years, we will get

1000 * 1.07^n

In that example, we want to know how much we will get after 20 years, so this is:

1000 * 1.07^{20}=3869.684462...

Thank you.

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Simplify 6-12b divided by 3a-6ab
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Answer:

\frac{2}{a}

Step-by-step explanation:

Given

\frac{6-12b}{3a-6ab} ← factor both numerator and denominator

= \frac{6(1-2b)}{3a(1-2b)} ← cancel common factor (1 - 2b) on numerator/denominator

= \frac{6}{3a} ← cancel 6 and 3 by 3

= \frac{2}{a}

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Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.
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For starters,

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Consider the nth partial sum, denoted by S_n:

S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n

Multiply both sides by \frac34:

\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}

Subtract S_n from this:

\dfrac34S_n-S_n=\dfrac1{16}\left(\dfrac34\right)^{n+1}-\dfrac1{16}\left(\dfrac34\right)

Solve for S_n:

-\dfrac14S_n=\dfrac3{64}\left(\left(\dfrac34\right)^n-1\right)

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