Answer: 80 pieces of fruit

Explanation:
Let’s find out the amount of trees Mr Champion has.
He has 14 in total. 1 apple tree and 1 plum tree, and the rest are divided evenly among apricot, pear and peach trees. This means:
1 apple tree + 1 plum tree = 2 trees
14 - 2 = 12 trees
12 / 3 (varieties of trees) = 4
In conclusion, he has
1 apple tree, 1 plum tree, 4 apricot, pear and peach trees.

Now let’s go to the section where he picks the fruit.
6 apricots from 4 trees
10 peaches from 4 trees
3 pears from 4 trees
4 apples from 1 tree

This means:
(6 x 4) + (10 x 4) + (3 x 4) + (4 x 1) = total pieces of fruit picked

24 + 40 + 12 + 4 = total pieces of fruit picked

Now, you add up those four numbers, and you have your answer, 80.

Hope this helps!

5 0

2 years ago

The following is an incomplete paragraph proving that the opposite angles of parallelogram ABCD are congruent:

kramer

<span>Pls. see attachment.
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6 0

3 years ago

Read 2 more answers

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago