Let the two numbers be x and y, then
x - y = 48 . . . (1)
x + y = 60 . . . (2)
(1) - (2) => -2y = -12 => y = -12/-2 = 6
From (1), x - 6 = 48 => x = 48 + 6 = 54
Therefore, the two numbers are 54 and 6.
1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span>
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
</span><span>x^2+20x+50=0
</span><span>
a=1
b=20
c=50
4. Therefore, when you simplify, the result is:
-10</span><span>±5</span>√2 (It is the last option).<span>
</span>
Answer:
hope it helps you......................
3^4 and 3^-6
multiply, add, subtract?
