Question

A black mamba snake has a length of 2.67 m and a top speed of 3.96 m/s . Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates at 1.47 m/s 2 from rest. How much time does it take the snake to reach its top speed?

Answer 1

Answer:

time (t) = 2.69 sec

Explanation:

Given that;

The final top speed of 3.96 m/s ( final velocity V) = 3.96 m/s .

The initial speed is 0; &

The acceleration (a) = 1.47 m/s²

We can determine how much time does it take the snake to reach its top speed by using the equation of motion;

V = U +at

3.96 = 0 + (1.47×t)

3.96 = 1.47t

t = $\frac{3.96}{1.47}$

time (t) = 2.69 sec

∴ It took the snake  2.69 sec to reach the its top speed.