It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.
The simplest polynomial with these characteristics would be

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

Answer:

Step-by-step explanation:
We have the equation of the position of the object

We need to solve the equation for the variable a

Subtract
and
on both sides of the equality


multiply by 2 on both sides of equality


Divide between
on both sides of the equation

Finally

Answer:
x=0
Step-by-step explanation:
If you combine like terms it is x^2 +6x -27=-27
x^2 +6x =0
x^2=0
x=0
Answer:
True
Step-by-step explanation:
When you have 2 negative together they will become a positive (5- (-2) = 7)
92% You would divide 69 by 75 then multiply by 100