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4 years ago

Divide, will mark brainliest.

Mathematics

2 answers:

Airida [17]4 years ago

6 0

Answer:

2 m^5 n^3 - m^4 n^2+4 m n

Step-by-step explanation:

6 m^6 n^4 - 3m^5 n^3 +12 m^2 n^2

--------------------------------------------------

3mn

Separate into 3 terms

6 m^6 n^4 3m^5 n^3 12 m^2 n^2

--------------- - ---------------- + -------------------

3mn 3mn 3mn

Simplify each term

6m^6 n^4/3mn = 6/3 m^(6-1) n^(4-1) = 2 m^5 n^3

3m^5 n^3/3mn = 3/3 m^(5-1) n^(3-1) = 1 m^4 n^2

12m^2 n^2/3mn = 12/3 m^(2-1) n^(2-1) = 4 m^1 n^1

Replacing into the equation

2 m^5 n^3 - 1 m^4 n^2+4 m^1 n^1

2 m^5 n^3 - m^4 n^2+4 m n

Brums [2.3K]4 years ago

3 0

Answer:

It is the top one

Step-by-step explanation:

Just divide each number by the denominator and subtract the exponents

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Anyone know??? X= ???

Lilit [14]

Answer:

x = 40.5

Step-by-step explanation:

2/3 * 40.5 = 27

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3 years ago

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Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born

NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

$p = \frac{31}{365} = 0.0849$

Group of 20 friends:

This means that $n = 20$

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773$

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

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3 years ago

What is 365 divided by 30

frozen [14]

In order to find this you must divide 365 by 30 to get a final answer of 12.17.

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4 years ago

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Two sides of a right triangle measure 7 units and 3 units.

stiks02 [169]

Answer:

Step-by-step explanation:

use the Pythagorean theorem to find the length of the third sides.

c²=a²+b²

c²=7²+3²

=49+9

=58

so, c²=√58

area of the square is 58 units

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4 years ago

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DerKrebs [107]

Answer:

<h2>12</h2><h2>Step-by-step explanation:</h2>

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