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2 years ago

15

A 500.-kilogram roller coaster starts from rest at the top of an 80.0-meter hill. What is its potential enegy halfway down the h

ill?

2 answers:

Anastaziya [24]2 years ago

8 0

Answer:

the answer is 200kg

Step-by-step explanation:

nydimaria [60]2 years ago

5 0

Answer: 392,000 J

Step-by-step explanation:

Ep=mgh

Ep=500(mass)9.8(gravity)80(height)

500•9.8•80=392,000 J

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If the Revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each, what is

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So,

All you have to do is find the total labor cost and put it over the revenue.

We have two workers each earning $8/hr. (lousy), and they work 40 hrs./week.

2 * $8 = $16/hr.

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$\frac{640}{2000}$

Cross out zeros.
$\frac{64}{200}$

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$\frac{2^3}{5^2}$
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If Jerry has four apples and you take away two how many does Jerry have

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3 years ago

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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC

jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

Firstly, we will find all angles and sides

Calculation of angle B:

we know that sum of all angles is 180

m∠A+ m∠B+m∠C=180

we can plug values

60°+ m∠B+45°=180

m∠B=75°

Calculation of BC:

we can use law of sines

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

now, we can plug values

$\frac{8}{sin(45)}=\frac{BC}{sin(60)}$

$BC=\frac{8}{sin(45)} \times sin(60)$

$BC=9.798$

Calculation of AC:

$\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

now, we can plug values

$\frac{8}{sin(45)}=\frac{AC}{sin(75)}$

$AC=\frac{8}{sin(45)} \times sin(75)$

$AC=10.928$

Perimeter:

$p=AB+BC+AC$

we can plug values

$p=10.928+8+9.798$

$p=28.726$

Area:

we can use formula

$A=\frac{1}{2}AB \times AC \times sin(A)$

now, we can plug values

$A=\frac{1}{2}8 \times 10.928 \times sin(60)$

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