7. -8/3
8. 4/35
9. -21/50
10. 35/64
11.-25/54
Answer:
The height of deepness of submarine is 424.1 feet
Step-by-step explanation:
Given as :
The angle at which submarine drives of the surface of water = Ф = 13°
The speed at which submarine travel = s = 760 feet per minute
Let The height of deepness of submarine = h feet
The time taken to reach that deepness = t = 5 minutes
<u>According to question</u>
The height of deepness of submarine = 
i.e h × cos(90 - Ф) = 
Or, h × Sin(Ф) = 
Or, h × Sin(13°) = 95 feet
Or, h × 0.224 = 95 feet
∴ h = 
i.e h = 424.10 feet
So, The height of deepness of submarine = h = 424.10 feet
Hence, The height of deepness of submarine is 424.1 feet Answer
Answer:
a). -65
b). -61
c). -20ab + 3bc +3ac
Step-by-step explanation:
According To the Question,
a). the sum of 72 − 104 + 5 and -32 + 4 - 10 .
- (72 − 104 + 5) + (-32 + 4 - 10)
- (-27) + (-38)
- -27 - 38
- -65
b). What should be added to 32 + 32 + 3 to get 3 + 3 , Let X be Added .
- Thus, (32 + 32 + 3) + X = 3 + 3
- 67 + X = 6
- X = 6 - 67
- X = -61
c). Subtract the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc – ac.
- Thus, [(ab + 2bc) + (3bc – ac)] - [( 12ab –10bc –18ac) + (9ab + 12bc + 14ac)]
- (ab + 5bc - ac) - (21ab + 2bc - 4ac)
- ab + 5bc - ac - 21ab - 2bc + 4ac
- -20ab + 3bc + 3ac
Answer:
The prize wheel diameter is 4.00 yards
Step-by-step explanation:
Area (A) = πd^2/4
πd^2 = 4A
d^2 = 4A/π
d (diameter) = √(4A/π)
A = 12.56 square yards, π = 3.142
d = √(4×12.56/3.142) = √15.99 = 4.00 yards