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3 years ago

9

HELP DUE AT 11:59!!!!!

2 answers:

faltersainse [42]3 years ago

5 0

Answer:

lmk if u ended up with a retake or sum sorry nobody got bk to before it was due

eimsori [14]3 years ago

5 0

Answer:

nryw j meyubhb3u4rts

Step-by-step explanation:

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How to solve 2/3(6x-9)=-34

castortr0y [4]

$\frac{2}{3} (6x-9)=-34 \\ \\ \frac{2(6x - 9)}{3} =-34 \\ \\ \frac{2 \times 3(2x-3)}{3} =-34 \\ \\ \frac{6(2x - 3)}{3} = -34 \\ \\ 2(2x - 3) = -34 \\ \\ 2x - 3 - \frac{34}{2} \\ \\ 2x - 3 = -17 \\ \\ 2x -17 + 3 \\ \\ 2x = -14 \\ \\ x = - \frac{14}{2} \\ \\ x = -7 \\ \\ Answer: \fbox {x = -7}$

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3 years ago

A one-parameter family of solutions of the de p' = p(1 − p) is given below.

tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$4 = \frac{c_{1}}{1 + c_{1}}$

$4 + 4c_{1} = c_{1}$

$c_{1} = -\frac{4}{3}$

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

Through the point (0, 1)?

Same thing as above

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$1 = \frac{c_{1}}{1 + c_{1}}$

$1 + c_{1} = c_{1}$

$0c_{1} = 1$

No solution.

So there is not a solution curve passing through the point(0,1).

3 0

3 years ago

What is 5 over 8 in decimal form

Sonja [21]

0.625 which is approximately equal to 0.63 is 5/8 in decimal form.

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2 years ago

Please help me with this problem! <br> y =<br><br> 37<br> 39<br> 51

nika2105 [10]

y = arctan(8/10)

y = 38.65

y = 39

8 0

2 years ago

Read 2 more answers

What property is [9 + (-9)] + (10x - 6x) + 3?

Roman55 [17]

So you're looking for the answer? If so, it is -3/4

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2 years ago