Describe how to graph a line given an equation in standard form.
1 answer:
This is pretty simple. So a standard form equation is probably something like this: 2x+8y=10.
We have to get that equation right there into a slope intercept, which is just isolating the variable y.
2x+8y=16
-2x -2x Subtract the x value.
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(8y=16-2x)/8 Divide the whole equation by 8 to isolate the y value.
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y=2-1/4x
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The fraction with the variable x is the slope. In this case, the slope is -1/4, so meaning it goes down one unit and goes right 4.
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The 2 is the y-intercept. (0, 2)
We have to get that equation right there into a slope intercept, which is just isolating the variable y.
2x+8y=16
-2x -2x Subtract the x value.
------------------
(8y=16-2x)/8 Divide the whole equation by 8 to isolate the y value.
------------------
y=2-1/4x
------------------
The fraction with the variable x is the slope. In this case, the slope is -1/4, so meaning it goes down one unit and goes right 4.
------------------
The 2 is the y-intercept. (0, 2)
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Answer:
6.6 cm and 14.6 cm
Step-by-step explanation:
(a)
the length of arc AB is calculated as
AB = circumference of circle × fraction of circle
= 2πr ×
= 2π × 4 ×
= 8π ×
=
≈ 6.6 cm ( to the nearest tenth )
(b)
the perimeter (P) of sector AOB is
P = r + r + AB = 4 + 4 + 6.6 = 14.6 cm
