To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.
I will show you calculation for (5,-2)
plug into y>x
-2>5
which is clearly false.
plug into y<x+1
-2<5+1
or -2<6
which is also false.
hence (5,-2) is not in the solution.
Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.
Hence answer will be "No Solution from given choices".
Answer:
a2
Step-by-step explanation:
you're using the pythagorean theorem
Answer:
Step-by-step explanation: 3root5x^2 + 25x - 10root5 = 0
3xroot5 + 25x - 10root5 = 0 [ root x^2 = x]
28x root5 = 10 root5 [ -10root5 turns to 10 root5 when transferred to RHS]
28x root 5/root5 =10
28x=10
x = 10/28
x = 0.35
Hope it helped u,
pls mark as the brainliest
^v^
