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Anika [276]
2 years ago
6

The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable

that is uniformly distributed) between 31 and 55 minutes. One student is selected at random. Find the probability of the following events.A. The student requires more than 51 minutes to complete the quiz.Probability =B. The student completes the quiz in a time between 35 and 42 minutes.Probability =C. The student completes the quiz in exactly 41.84 minutes.Probability =
Mathematics
1 answer:
laiz [17]2 years ago
8 0

Answer:

(a) The probability that a student requires more than 51 minutes to complete the quiz is 0.1667.

(b) The probability that a student completes the quiz in a time between 35 and 42 minutes is 0.2917.

(c) The probability that a student completes the quiz in exactly 41.84 minutes is 0.0417.

Step-by-step explanation:

Let <em>X</em> = amount of time it takes for a student to complete a statistics quiz.

The random variable <em>X</em> is uniformly distributed with parameters <em>a</em> = 31 minutes and <em>b</em> = 55 minutes.  

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(a)

Compute the probability that a student requires more than 51 minutes to complete the quiz as follows:

P(X>51)=\int\limits^{55}_{51} {\frac{1}{55-31}}}\, dx=\frac{1}{24} |x|^{55}_{51}=\frac{55-51}{24}=0.1667

Thus, the probability that a student requires more than 51 minutes to complete the quiz is 0.1667.

(b)

Compute the probability that a student completes the quiz in a time between 35 and 42 minutes as follows:

P(35

Thus, the probability that a student completes the quiz in a time between 35 and 42 minutes is 0.2917.

(c)

Compute the probability that a student completes the quiz in exactly 41.84 minutes as follows:

Apply continuity correction as follows:

P (X = 41.84) = P (41.84 - 0.50 < X < 41.84 + 0.50)

                     = P (41.34 < X < 42.34)

=\int\limits^{42.34}_{41.34} {\frac{1}{55-31}}}\, dx=\frac{1}{24} |x|^{42.34}_{41.34}=\frac{42.34-41.34}{24}=0.0417

Thus, the probability that a student completes the quiz in exactly 41.84 minutes is 0.0417.

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What’s the correct answer for this?
slava [35]

Answer:

1/4

Step-by-step explanation:

Let's denote the probabilities as following:

Probability that a teenager has a sister:

P(A) = 12/28

Probability that a teenager has a brother:

P(B) = 7/28

Probability that a teenager has both a sister and a brother:

P(A⋂B) = 3/28

Probability that a selected teenager has a sister also has a brother, or in other words, he/she has a brother, given he/she had a sister:

P(B|A)

Let's apply the formula of conditional probability to work out P(B|A)

P(B|A) = P(A⋂B)/P(A) = (3/28)/(12/28) = (3*28)/(12*28) = 3/12 = 1/4

=> Option C is correct

Hope this helps!

7 0
3 years ago
Having trouble w graphing :(
NISA [10]

6x/6=x>/= (=) 11/6

x=11/6 or about 1.8

the first important notation to remember when graphing inequalities is that the graph is going to face the way the inequality sign is pointing.

in this case, the sign is pointing right. now the second thing to remember is that an inequality sign with a line underneath it means that it is greater/equal to so the graph in which we fill will have be a closed circle

1) start the ray at ~1.8 and fill in the circle at the end of the ray then extend to its endpoint

that's all. you're graph now reads  x is greater or equal to 11/6

3 0
3 years ago
A trailer will be used to transport several 40-pound crates to a store. The greatest amount of weight that can be loaded into th
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Given :

A trailer will be used to transport several 40-pound crates to a store.

The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.

An 82-pound crate has already been loaded onto the trailer.

To Find :

The greatest number of 40-pound crates that can be loaded onto the trailer.

Solution :

Weight left = 1050 - 80 = 970 pound.

Let, number of 40 pounds crates that can be loaded are x.

x  = \dfrac{970}{40}\\\\x = 24.25

Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.

Hence, this is the required solution.

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2 years ago
How do you do this?
evablogger [386]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Burka [1]

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4 0
3 years ago
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