Answer:
Hey mate.....
Explanation:
This is ur answer.....
<em>To remove the last n elements from an array, use arr. splice(-n) (note the "p" in "splice"). The return value will be a new array containing the removed elements.</em>
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Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
Answer:
-3874₁₀ = 1111 1111 1111 1111 1111 1111 1101 1110₂
Explanation:
2's complement is a way for us to represent negative numbers in binary.
To get 2's complement:
1. Invert all the bits
2. Add 1 to the inverted bits
Summary: 2's complement = -N = ~N + 1
1. Inverting the number
3874₁₀ = 1111 0010 0010₂
~3874₁₀ = 0000 1101 1101₂
2. Add 1 to your inverted bits
~3874₁₀ + 1 = 0000 1101 1101₂ + 1
= 0000 1101 1110₂
You can pad the most signigicant bits with 1's if you're planning on using more bits.
so,
12 bits 16 bits
0000 1101 1110₂ = 1111 0000 1101 1110₂
They asked for double word-length (a fancy term for 32-bits), so pad the left-most side with 1s' until you get a total of 32 bits.
32 bits
= 1111 1111 1111 1111 1111 1111 1101 1110
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Answer:
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Explanation:
