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3 years ago

_ models are non visual ways of communicating how someone thinks about something in the natural world

Computers and Technology

1 answer:

bezimeni [28]3 years ago

7 0

Idea models are non visual ways of communicating how someone thinks about something in the natural world.

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In Java, it is possible to create an infinite loop out of while and do loops, but not for-loops. true or false

soldier1979 [14.2K]

Answer:

False is the correct answer for the above question.

Explanation:

In java programming language or any other programming language, any loop can be infinite.
It is because the infinite loop is called for that loop which is not run in a finite number of times.
The loop is used to repeat some lines in a finite number of times. Any loop has three things- first is the initial value which tells the loop to start, The second is the condition check which states when the loop will stop and the third is an operation which directs some variable, so that the condition may be false after some finite amount of time.
If the condition will not false in any iteration of the loop, then the loop can proceed for an infinite amount of time.
The above-question states that the while loop and do while loop can be infinite which is a true statement.
But it also states that the 'for' loop can not be infinite which is not a correct statement which is described above. Hence false is the correct answer to the above question.

8 0

3 years ago

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

3 years ago

The five types of personal computers are: desktops, laptops, tablets, smartphones, and

shepuryov [24]

Answer:

microcomputers

Explanation:

8 0

3 years ago

A(n) _______________ supplies one of the most critical aspects of docking stations, but in a smaller, more portable format: supp

baherus [9]

Answer:

A Port Replicators.

Explanation:

Port replicators are devices or extension. They are plugged into the laptop's usb port to provide extra ports to connect other external devices needed by the laptop.

Docking stations does the same thing, but the laptop is plugged into the docking station holding the needed devices, and meant for that laptop brand.

7 0

3 years ago

Yooooooooooooooo

patriot [66]

Answer:

A-A Boolean search

Explanation:

8 0

2 years ago

Read 2 more answers