4 years ago

What is the solution set for this inequality -8-7<57

1 answer:

5 0

Answer:

The answer is -15<57 which is true.

Step-by-step explanation:

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kenny6666 [7]

The answer is 54 hope this helps.

3 0

3 years ago

tekilochka [14]

15.20 would be the tip

Hope this helps :)

6 0

4 years ago

Nataly [62]

Since there are only 4 terms in the sum, it's not too much work to expand it as

$\displaystyle \sum_{n=0}^3 (2n-3) = -3 + (-1) + 1 + 3 = \boxed{0}$

Alternatively, we can use the well-known formulas

$\displaystyle \sum_{n=1}^N 1 = \underbrace{1 + 1 + \cdots + 1}_{N \text{ 1s}} = N$

$\displaystyle \sum_{n=1}^N n = 1+2+\cdots+N = \frac{N(N+1)}2$

These sums start at n = 0, so in our given sum we will keep track of the 0-th term separately:

$\displaystyle \sum_{n=0}^3 (2n-3) = -3 + \sum_{n=1}^3 (2n-3) = -3 + 2 \sum_{n=1}^3 n - 3 \sum_{n=1}^3 1 = -3 + 3\times4 - 3\times3 = 0$

as expected.

8 0

2 years ago

e-lub [12.9K]

7x+5
Hope this helps

7 0

3 years ago

Lana71 [14]

We need base

Apply Pythagorean theorem

7 0

2 years ago