Answer:
The correct option is;
Increasing one fifth unit/sec
Step-by-step explanation:
The equation that gives the curve of the particle of the particle is y = 5·x² - 1
The rate of decrease of the y value dy/dt = 2 units per second
We have;
dy/dx = dy/dt × dt/dx
dy/dx = 10·x
dy/dt = 2 units/sec
dt/dx = (dy/dx)/(dy/dt)
dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)
When x = 1
dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec
dx/dt = 1/5 unit/sec
Therefore, x is increasing one fifth unit/sec.
Answer:
...
Step-by-step explanation:
umm... honestly we will NEVER use this in the real world ♂️
Answer:
k = 7.3333333 ...
You can round accordingly of write the fraction form
Step-by-step explanation:
4/k = 6/11
6 ÷ 4 = 1.5
11 ÷ 1.5 = 7.3333333 ... (repeating)
4/7.333 = 6/11
11 more than five of a certain number would be written as 5x+11 and it is (means equal to) twenty more than two times that number, which would be 2x+20. So the equation would be
5x+11=2x+20
-2x -2x (get the x's on one side)
3x+11=20
-11 -11 (get the numbers on one side)
3x=9
/3 /3 (divide by 3, so you can get the x by itself)
X=3 (the number is 3)
Answer:
A
Step-by-step explanation:
To find (f ￮ g)(x) substitute x = g(x) into f(x), that is
f(g(x))
= f(2x - 1)
= 3(2x - 1) + 14
= 6x - 3 + 14
= 6x + 11 → A
