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eimsori [14]
3 years ago
5

What is the sum of the first 10,000 positive integers?

Mathematics
1 answer:
blagie [28]3 years ago
7 0
The sum of the first n positive integers can be easily found using Gauss' method.

\sum\limits_{i=1}^n i=\dfrac{n(n+1)}{2}\\\\
\sum\limits_{i=1}^{10,000} i=\dfrac{10,000(10,000+1)}{2}\\
\sum\limits_{i=1}^{10,000} i=\dfrac{10,000 \cdot10,001}{2}\\
\sum\limits_{i=1}^{10,000} i=50,005
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What is the percent of decrease from 2,000 to 1,000?
IgorLugansk [536]

Answer:

50%

Step-by-step explanation:

2,000 is 2 x more than 1,000. Or, 1,000 is half of 2,000 and half of 100%=50%.

7 0
4 years ago
Alicia can paint a small room 21 hours faster than Nina aloneness 4 hours slower than Alicia and Nina together. How long will it
Alexeev081 [22]

Answer:

11.413 Hours.

Step-by-step explanation:

Alicia can paint a house in 21 hours; Which means in 1 hour she can paint 1/24 of the house.

Nina can paint the same house in (21+4)  hours. Which means in 1 hour she can paint 1/25 of the house.

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7 0
3 years ago
Find the missing segment in the image below
makvit [3.9K]

Answer:

The missing segment length is 20.

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7 0
3 years ago
Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the
NeTakaya

Answer:

CI ≈ (173.8 < μ < 196.2)

Step-by-step explanation:

We are told that laboratory tested twelve chicken eggs. Thus;

n = 12

Mean; x¯ = 185 mg

S.D; s = 17.6 mg

DF = n - 1 = 12 - 1 = 11

We have a 95% confidence level. Thus; α = 0.05

Since n < 30, we will use t-sample test.

Thus, from t-table attached at 95% Confidence level and DF = 11, we have;

t = 2.201

Thus,formula for Confidence interval is;

CI = (x¯ - t(s/√n)) < μ < (x¯ + t(s/√n))

CI = (185 - 2.201(17.6/√12)) < μ < (185 + 2.201(17.6/√12))

CI = (185 - 11.1825) < μ < (185 + 11.1825)

CI = (173.8175 < μ < 196.1825)

CI ≈ (173.8 < μ < 196.2)

7 0
3 years ago
How do i deleted a question on here lol
shtirl [24]
I don’t think you can lol
8 0
3 years ago
Read 2 more answers
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