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kodGreya [7K]
3 years ago
15

Which number line shows the correct placement of 10%, 14, and 34?

Mathematics
2 answers:
BigorU [14]3 years ago
5 0
From what I got. . . It would be closer to the 3 box next to (0, 10%, 1/4, 3/4, 1)
So the box with the close answer would be [0--1/4----3/4---1------------10]
That's what I got when I try solving it
NeX [460]3 years ago
4 0
The first one, or the one that has 10% first.
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I need help please. Must be correct. 10 points. Thanks
Anna11 [10]

We have the supplementary angles.

The sum of the measures of the two Supplementary Angles is 180°.

Therefore we have the equation:

13x - 2 + 39 = 180

13x + 37 = 180     <em>subtract 37 from both sides</em>

13x = 143      <em>divide both sides by 13</em>

<em>x = 11</em>

<h3>Answer: 11</h3>
5 0
3 years ago
If you know the rate of a water leak in gallons per hour, how can you find the number of hours it takes for 1 gallon to leak out
Evgen [1.6K]

1/the rate of leakage per hour

This will give you the time it takes for 1 gallon to leak out in hours.  

For example, if something is leaking at the rate of 12 gallons per hour, it will take 1/12 of an hour for 1 gallon to leak out. ( or 5 min)

7 0
3 years ago
What is the side length of a square with a perimeter of 60 meters
konstantin123 [22]

Answer:

15 meters each side

Step-by-step explanation:

60/4 = 15

7 0
3 years ago
Pls Help <br> Construction Quiz
pochemuha

Answer:

Angle Bisector

the arc was constructed were the two lines met making it to form an angle

7 0
1 year ago
I cant figure this one out at all
eduard

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

4 0
2 years ago
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