1) subtract 2y in both sides: (7y-2y)-6=(2y-2y)+8 which is 5y-6=8
2) Add 6 to both sides: 5y(-6+6)=8+6 which is 5y=14
3) Divide 5 on both sides: 5y/5=14/5 which is y=14/5 or y=2.8 or y=2 4/5

5 0

3 years ago

Read 2 more answers

a hardware factory produces 3.6 •10^5 bolts in 2400 minutes. what is the factory rate of production in bolts per minute

Ainat [17]

10^5=100,000
100,000*3.6
360,000
360,000/2400

I believe it’s 150 bolts per minute

5 0

3 years ago

Which of the following are statistical questions? Select all that apply.

Olegator [25]

The answers are a b c d e or all of them except the chocolate chip one

5 0

2 years ago

1. Writing an equation for an exponential function by

Naya [18.7K]

Answer: 1) $t(n)=0.6(2)^n$

2) $f(x)=10(5)^x$

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

$t(n) = ab^n$ ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

$0.6 = a(b)^0\implies 0.6 = a$

Hence the function that shows the given situation,

$t(n) = 0.6 b^n$ -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

$1.2 = 0.6 b^1\implies 2 = b$

Thus, the complete function is,

$t(n) = 0.6 (2)^n$

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = ab^x$ ---------(1)

For f(x) = 2, x = -1

By equation (1),

$2= ab^{-1}$ ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

$\frac{2}{5}= a(b)^{-2}$

$\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}$

$\implies \frac{2}{5}=\frac{2}{b}$

$\implies 2b=10$

$\implies b = 5$

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = 10(5)^x$

5 0

2 years ago