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3 years ago

15

What is the answer 7÷5,631 eqall

1 answer:

otez555 [7]3 years ago

3 0

7/5,631=0.0012431185

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Arlene makes a necklace using 14 purple beads for every 6 silver beads. The necklace contains 18 beads. How many of each color b

Margaret [11]

Answer:

5.4 numbers of purple beads and 12.6 numbers of silver beads.

Step-by-step explanation:

Arlene makes a necklace using 14 purple beads for every 6 silver beads. So, she uses purple and silver beads in the ratio 14 : 6 = 7 : 3.

Now, the necklace contains 18 beads, then in the ratio 7 : 3, there will be $(18 \times \frac{3}{3 + 7}) = 5.4$ numbers of purple beads and (18 - 5.4) = 12.6 numbers of silver beads. (Answer)

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3 years ago

Help please............

tigry1 [53]

Answer:

$\tan(J) =\frac{5\sqrt{66}}{66}$

Step-by-step explanation:

$\tan(J) =\frac{5}{\sqrt{66}}$

$\tan(J) =\frac{5}{\sqrt{66}} \times \frac{\sqrt{66}}{\sqrt{66}}$

$\tan(J) =\frac{5\sqrt{66}}{\sqrt{66}\times\sqrt{66} }$

$\tan(J) =\frac{5\sqrt{66}}{66}$

5 0

3 years ago

Solve for x with 45 degree angle & 60ft side

Alona [7]

Answer:

x = 84.85281374 ft

Step-by-step explanation:

We know that sin theta = opposite/ hypotenuse

sin 45 = 60/x

Multiply each side by x

x * sin45 = 60/x*x

x sin 45 = 60

Divide each side by sin 45

x = 60/sin 45

x = 84.85281374 ft

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3 years ago

Convert 4 gallons to pints (1 gallon = 4 quarts; 1 quart = 2 pints)

Rina8888 [55]

Answer:

32

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

The twice–differentiable function f is defined for all real numbers and satisfies the following conditions: f(0)=3 f′(0)=5 f″(0)

Vladimir79 [104]

$g(x)=e^{ax}+f(x)\implies g'(x)=ae^{ax}+f'(x)\implies g''(x)=a^2e^{ax}+f''(x)$

Given that $f'(0)=5$ and $f''(0)=7$ , it follows that

$g'(0)=a+5$

$g''(0)=a^2+7$

###

$h(x)=\cos(kx)f(x)+\sin x\implies h'(x)=-k\sin(kx)f(x)+\cos(kx)f'(x)+\cos x$

When $x=0$ , we have

$h(0)=\cos0f(0)+\sin0=f(0)=3$

The slope of the line tangent to $h(x)$ at (0, 3) has slope $h'(0)$ ,

$h'(0)=-k\sin0f(0)+\cos0f'(0)+\cos0=5+1=6$

Then the tangent line at this point has equation

$y-3=6(x-0)\implies y=6x+3$

###

Differentiating both sides of

$4x^2+y^2=48+2xy$

with respect to $x$ yields

$8x+2y\dfrac{\mathrm dy}{\mathrm dx}=2y+2x\dfrac{\mathrm dy}{\mathrm dx}$

$\implies(2y-2x)\dfrac{\mathrm dy}{\mathrm dx}=2y-8x$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y-4x}{y-x}$

On this curve, when $x=2$ we have

$4(2)^2+y^2=48+2(2)y\implies y^2-4y-32=(y-8)(y+4)=0\implies y=8$

(ignoring the negative solution because we don't care about it)

The tangent to this curve at the point $(x,y)$ has slope $\dfrac{\mathrm dy}{\mathrm dx}$ . This tangent line is horizontal when its slope is 0. This happens for

$\dfrac{y-4x}{y-x}=0\implies y-4x=0\implies y=4x$

and when $x=2$ , there is a horizontal tangent line to the curve at the point (2, 8).

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3 years ago