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Westkost [7]
3 years ago
13

Help me..............

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0
V = <span>πr^2h
so
r^2 = V/(</span><span>πh)
r = </span>√V/(πh)
r = √(Vπh) / πh

answer is D. last one
r = √(Vπh) / πh

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Mr. Wilson bought a bag of birdseed and put half of it in his bird feeder. He split the other half equally among his 4 pet birds
pickupchik [31]

Answer:

each pet bird got 1/8 of the bag of birdseed

Step-by-step explanation:

the easiest way to do this is to divide the bag into eighths. if you divide the bag into eighths, 4/8 of the bag, being half, goes into the bird feeder. the other 4/8 of the bag is divided among Mr. Wilson's four pet birds, leaving each bird to get 1/4 of the bag when split evenly.

hope this helps

5 0
3 years ago
[Problem Solving 2] *
Ksenya-84 [330]

Answer:

5

Step-by-step explanation:

each daughter has 2 sisters and 2 brothers but each son had 1 brother and 3 sisters

7 0
4 years ago
Read 2 more answers
An office store pays a whole price of $120 for a laser printer and sells it for $174. What is the pecent mark up
Advocard [28]

Answer:

its by 54%

Step-by-step explanation:

because it is raising the price by making money by 54%. and that its using the calculator in any way.

8 0
3 years ago
Find a third-degree polynomial equation with rational coefficients that has roots -4 and 6 + i.
dolphi86 [110]

Answer:

x³ - 8x² - 11x + 148

Step-by-step explanation:

Given that x = 6 + i is a root then x = 6 - i is also a root

Complex roots occur as conjugate pairs.

The factors are therefore (x - (6 + i)) and(x - (6 - i))

Given x = - 4 is a root then (x + 4) is a factor

The polynomial is the product of the factors, that is

p(x) = (x + 4)(x - (6 + i))(x - (6 - i))

      = (x + 4)(x - 6 - i)(x - 6 + i)

      = (x + 4)((x - 6)² - i²)

      = (x + 4)(x² - 12x + 36 + 1)

      = (x + 4)(x² - 12x + 37) ← distribute

      = x³ + 4x² - 12x² - 48x + 37x + 148

      = x³ - 8x² - 11x + 148

 

3 0
3 years ago
2,5, 25/2, ... <br> find the 10th term
notka56 [123]

Answer:

The  10^{th} term of the given sequence

t_{10} = \frac{5^{9} }{2^{8} }

Step-by-step explanation:

<u>Step(i):-</u>

Given sequence   2 , 5, \frac{25}{2}

First term    a = 2

The difference of given geometric sequence

    d = \frac{r_{2} }{r_{1} } = \frac{5}{2}

<u><em>Step(ii):-</em></u>

The  n^{th} term of the given sequence

t_{n} = ar^{n-1}

The  10^{th} term of the given sequence

t_{10} = (2)(\frac{5}{2} )^{10-1}

t_{10} = (2)(\frac{5}{2} )^{9}= \frac{5^{9} }{2^{8} }

8 0
3 years ago
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