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3 years ago

Help me..............

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

7 0

V = <span>πr^2h
so
r^2 = V/(</span><span>πh)
r = </span>√V/(πh)
r = √(Vπh) / πh

answer is D. last one
r = √(Vπh) / πh

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Mikhail recorded the heights of all the male students in his math class. The results, in inches, are: 52, 55, 56, 60, 53, 51, 64

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Mikhail recorded the heights of all the male students in his math class. The results, in inches, are: 52, 55, 56, 60, 53, 51, 64, 67, 61, 58. Which type of graph would best display the heights in the 50 to 59 and the 60 to 69 inch range for comparison?

Solution: Stem and leaf plot would best display the heights in the 50 to 59 and the 60 to 69 inch range for comparison.

Stem-and-leaf plots are a method for showing the frequency with which certain classes of values occur. The stem and leaf plot is used like a histogram; it allows us to compare data. While a histogram uses bars to represent amounts, the leaves of the stem-plot represent amounts.

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Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

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The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

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$\alpha = 0.05$

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$n \ \ \alpha \ \ \frac{1}{E^2 }$

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Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

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Answer:

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