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algol [13]
3 years ago
12

Vicki would like to estimate the probability of tails coming up fewer than 2 times in 3 coin flips. To do this, she has a comput

er randomly select 0 or 1 three times, with 0 representing heads and 1 representing tails. The results of 15 trials are shown in the table.
What is Vicki's estimated probability, based on this simulation?

Enter your answer as a fraction, in simplified form, in the box.
Mathematics
2 answers:
juin [17]3 years ago
7 0

Answer:

2/5

Step-by-step explanation:

i took the test and got it correct. please like and rate my answer.

brainliest please?

a_sh-v [17]3 years ago
6 0
The answer is 6 for a quick answer 
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<u>Step-by-step explanation:</u>

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3 0
3 years ago
A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li
hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0
3 years ago
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5 0
3 years ago
Express 134.78 correct to the nearest tenth​
monitta

Answer:

134.8 is the answer

Step-by-step explanation:

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3 years ago
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Area of a rectangle = length x width

3/4 x 5/12 = 15/48
15/48 = 5/16
The area of Kurt's maze is 5/16 square feet.
7 0
3 years ago
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