Answer: last option
Step-by-step explanation:
You know that the weight of his pumpkin 4.9 pounds and that, if he guesses its weight within 0.3 pounds, he will get the pumpkin for free.
Then, to find the minimum weight he can guess in order to get his pumpkin for free, it's necessary to write the expression:

Rewriting it:

To find the maximum weight he can guess in order to get his pumpkin for free, it's necessary to write the expression:

Rewriting it:

Answer:
-7π/3 or -420 degrees
Step-by-step explanation:
So we know that the arrow has made one full rotation and that it is moving in a clockwise direction. So already we have -2π degrees.
The arrow stops at π/6 before the next π/2 rotation. Therefore we find the difference between the two.
π/2 - π/6
3π/6 - π/6 = 2π/6
π/3
Since this is still clockwise, we make this negative. So the measure of the angle shown by the arrow is -2π - π/3
Answer:
144A+3AC
Step-by-step explanation:
I think you provided half of the problem. Because this does not make sense to any problem I can think of.
Answer:
Yes.
Step-by-step explanation:
Exponential Parent Function: 
If we write out the equation:

Whenever we have an exponent of <em>x</em>, it is a exponential function. The 5 is simply the base of the exponent and the 6 means we are vertically stretching the graph by a factor of 6.