All categories

2 years ago

5. Find the value of x that makes BC || DE.

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

8 0

Answer:

x = -7

Step-by-step explanation:

To find the value of x, you need to set up a proportion:

$\frac{x-2}{15}$ = $\frac{x-1}{18}$

Then cross multiply:

15x - 15 = 18x + 36

Then subtract 15x from both sides:

-15 = 3x + 36

Subtract 36 from both sides:

-51 = 3x

Finally, divide both sides by 3:

x = -7

You might be interested in

The business department at a university has 18 faculty members. Of them, 11 are in favor of the proposition that all MBA student

drek231 [11]

Answer:

0.225

Step-by-step explanation:

Total outcomes of choosing 5 out of 18 members = 18C5

Outcomes of choosing 2 out 11 favourers, 3 out of 7 members = 11C2 & 7C3

Probability = Favourable outcomes / Total outcomes

= ( 11C2 x 7C3 ) / 18C5

[ 18 ! / 5! 13! ]

( 55 x 35 ) / 8568

1925 / 8568

= 0.2246 ≈ 0.225

8 0

2 years ago

Malia is booking train tickets for her family. Tickets cost $75 per adult, $50 per senior or per person between the ages of 12 a

soldi70 [24.7K]

Answer:235$

Step-by-step explanation:

8 0

3 years ago

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

2 years ago

Voltage sags and swells. The power quality of a transformer is measured by the quality of the voltage. Two causes of poor power

zysi [14]

Answer:

$z-score = 1.57$

$z-score_s = -3.36$

Step-by-step explanation:

From the question we are told that

The sample size is n = 103

The sample mean of sag is $\= x_1 = 353$

The sample mean of swells is $\= x_2 = 184$

The standard deviation of sag is $s_1 = 30$

The standard deviation of swells is $s_2 = 25$

The number of swell for a randomly selected transformer is k = 100

The number of sag for a randomly selected transformer is c = 400

Generally the z-score for the number of swells is mathematically represented as

$z-score_s = \frac{ k - \= x_2}{s_2}$

=> $z-score_s = \frac{ 100- 184}{25}$

=> $z-score_s = -3.36$

Generally the z-score for the number of sags is mathematically represented as

$z-score = \frac{ c - \= x_1}{s_1}$

$z-score = \frac{ 400 - 353}{30}$

$z-score = 1.57$

4 0

3 years ago

Which statement describes whether a right triangle can be formed using one side length from each of these squares?

balu736 [363]

Answer:

Step-by-step explanation:

The area of the given squares are

Area = 64 in

Area = 225 in

Area = 289 in

The length of each side of a square is determined by finding the square root of its area. For the first square, the length of its side is √64 = 8inches. For the second square, the length of its side is √225 = 15inches. For the third square, the length of its side is √289 = 17inches.

For a right angle triangle to be formed, Pythagorean theorem must be obeyed. Sum of the square of the smaller sides must equal the square of the longer side. Therefore,

8² + 15² = 17²

289 = 289

Therefore, the correct statement is

Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square

4 0

2 years ago