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ivann1987 [24]
3 years ago
15

What percent if 6 is 1.2

Mathematics
2 answers:
Nataliya [291]3 years ago
6 0
What percentage of 6 is 1.2

\dfrac{1.2}{6}  \times 100 = 20%

Answer: 1.2 is <u>20%</u> of 6
natulia [17]3 years ago
3 0
Answer:  "<u /> <u>20 % </u>" of 6  is 1.2 " . 
______________________________________________________
Explanation:
______________________________________________________
" What percent OF "6" is "1.2" ? "
______________________________________________________
{ n/100 } * 6 = 1.2 ;   Solve for "n" ; 

Divide each side of the equation by "6" ; 

to get: 

n/100 = 1.2 / 6 ; 

→ n / 100 = 0.2 ; 

Multiply each side of the equation by "100" ; 
    to isolate "n" on one side of the equation; & to solve for "n" ; 

→ n = (0.2) * 100 ; 

→ n = "20" . 

Answer:  "20 % of 6 is 12 " . 
_______________________________________
Alternate method:

(n/100) * 6 = 1.2 ; 

(n/100) * (6/1) = 1.2 ; 

6n/ 100 = 1.2 ; 

6n = 1.2 * 100  ;

6n = 120 ; 

Divide each side of the equation by "6" ; 
to isolate "n" on one side of the equation; & to solve for "n" ; 

6n / 6 = 120 / 6 ; 

n = "20" 
_________________________
→  "20 %" of 6 is 1.2 " . 
_________________________
Alternate method:
__________________________
n/100   * 6 = 1.2 ; 

→ 6n / 100 = 1.2 ; 

→ 3n / 50 = 1.2 ; 

→ 3n = 1.2 * 50 ; 

→ 3n =  60.0

→ 3n = 60 ; 

Divide each side of the equation by "3" ; 
to isolate "n" on one side of the equation; & to solve for "n" ; 

→  3n/ 3 = 60 / 3 ; 

→ n = "20" ; 

Answer:  " 20 % " of 6 is 1.2 " . 
__________________________________________________
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Consider the function f(x)=x2e4x. f(x) has two inflection points at x = C and x = D with C≤D where C is and D is Finally for eac
fredd [130]

Answer:

the inflection points are

x = -0.85, -0.14

So,

C = -0.85 \\D = -0.14

It is concave down at the intervals

(-\infty , -0.85] \cup [-0.14,\infty)

And it would be concave up at

(-0.85 , -0.14)

Step-by-step explanation:

Remember that to find inflection points you need to find where

f''(x) = 0

Since

f(x) = x^2 e^{4x}

Then using the product and the chain rule you have that

f'(x) = 2e^{4x} x(2x+1)

And then, using again the chain rule and the product rule you have that

f''(x) = 2e^{4x} (8x^2 +8x+1)

Therefore you have to solve the equation

8x^2 +8x+1 = 0

Using the quadratic equation you get that there are two solutions, so the inflection points are

x = -0.85, -0.14

So,  

C = -0.85 \\D = -0.14

Now remember that a function is concave up if the derivative is greater than zero and concave down if the derivative is less than zero. Therefor you have to solve these inequalties

8x^2 +8x+1  < 0 \\8x^2 +8x+1 \geq 0

And you would get that is concave down at the intervals

(-\infty , -0.85] \cup [-0.14,\infty)

And it would be concave up at

(-0.85 , -0.14)

8 0
3 years ago
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