Answer:
X=10, x=4
Step-by-step explanation:
first, divide 14 by 2, and square it; giving you
x^2-14x+(7)^2=-40
Because 7^2 is 49, you have to add 49 to the other side; giving you
x^2-14x+(7)^2=9
Then factor the left side; giving you (x-7)^2=9
Take the square root of both sides, giving you
(x-7)^2= plus or minus 3
Then solve to get two solutions, 10 and 4
Answer: The total cost of the fences=$165.6
Step-by-step explanation:
Let a = the length of the side if the square.
The perimeter of the square is 60 ft
4a = 60ft
divide both sides by
4a = 60/4
a = 15 ft
The garden is surrounded by two fences, one fence is around the perimeter of the garden, whereas the second fence is 3 feet from the first fence on the outside
Expand to get:
4*a + 4(a + 2*3)
Replace a with 15 to get:
= 4*15 + 4(15 + 6) 60 + 4(21) 60+84
= 144ft
The cost of the fence is $1.15 per foot
The cost of 144 ft fence will be:
= 144*1.15
= $165.6
Learn more about event correlation here: brainly.com/question/1333555
#21165
Answer:
560 ft/min
Step-by-step explanation:
Let r represent Samantha's running rate in feet per minute. Then r-230 is her walking rate. We can use the relation ...
distance = speed × time
to write an equation for the total distance Samantha went.
20r + 15(r -230) = 16150
35r - 3450 = 16150 . . . . eliminate parentheses, collect terms
35r = 19600 . . . . . . . . . . add 3450
r = 560 . . . . . . . . . . . . . . divide by the coefficient of r
Samantha ran 560 feet per minute.
Check the picture below.
so... you can pretty much see how long RS and QT are, you can just count the units off the grid.
now, let's find QR's length

and let's also find the length for ST

so, add the lengths of all sides, and that's the perimeter of the trapezoid.
Answer: Our required values would be -10x+5, 2x+5 and -25.
Step-by-step explanation:
Since we have given that
g(x) = -4x+5
and
h(x) = 6x
We need to find (g-h)(x) and (g+h)(x).
So, (g-h)(x) is given by

and (g+h)(x) is given by

and (g-h)(3) is given by

Hence, our required values would be -10x+5, 2x+5 and -25.