Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a 
b 
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:




Solving (b): Probability that none are defective.
The probability that a selection is not defective is:

For two selections, the probability that all are not defective is:




Answer:
3 = ?
Step-by-step explanation:
The triangles are similar, so we can use ratios
15 12 -2
------ = --------------
15+? 12
15 10
------ = --------------
15+? 12
Using cross products
15 * 12 = 10 ( 15+?)
180 = 10 ( 15+?)
Divide each side by 10
18 = 15+?
Subtract 15 from each side
18-15 = 15+?-15
3 = ?
Answer:
I think the second one is the answer ; 2√b
Answer:
<u>240cm³</u>
Step-by-step explanation:
To find our answer we will <u>multiply</u> the <em>volume, width, and height</em>.
4 · 20 · 3 = 240. Therefore, <u>240cm³ is our answer.</u>
<em>Have a good day!</em>