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Masja [62]
3 years ago
9

Solve for y: -2(5y-1)-y=-4(y-3)

Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer:

<h2>y =  -  \frac{10}{7}</h2>

Step-by-step explanation:

- 2(5y - 1) - y = - 4(y - 3)

Expand the terms in the bracket

That's

-10y + 2 - y = - 4y + 12

Group like terms

Send the constants to the right side of the equation and those with variables to the left side

That's

- 10y - y + 4y = 12 - 2

- 7y = 10

Divide both sides by - 7

We have the final answer as

<h3>y =  -  \frac{10}{7}</h3>

Hope this helps you

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Ax + z = aw - y<br> Solve for a
olga2289 [7]
Ax=aw-z-y
divide by x
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8 0
3 years ago
FRANK has a paper clip.it has a mass of 9g and a volume of 3cm3.what is its density?
Pachacha [2.7K]

Answer:

<h2>3 g/cm³</h2>

Step-by-step explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =   \frac{9}{3}  = 3 \\

We have the final answer as

<h3>3 g/cm³</h3>

Hope this helps you

7 0
2 years ago
Find c. Round to the nearest tenth.
mixer [17]

Answer:

Here,

150+10=180

162-180=18

Answer is 18°

Step-by-step explanation:

So the round of nearest tenth is 18°

Hope it will help have a great day at school. ^_^

3 0
3 years ago
Helppppppppppppppppppppppp!!!!!!!!!! Plz
taurus [48]

Answer:

a

Step-by-step explanation:

the answer is a as proven by the othee options being false

4 0
3 years ago
Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...​
rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

x_n = a n^4 + b n^3 + c n^2 + d n + e

From the given known values of the sequence, we have

\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}

Solving the system yields coefficients

a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4

so that the n-th term in the sequence might be

\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}

Then the next few terms in the sequence could very well be

\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of \{x_n\} eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of \{x_n\} by \Delta^{k}\{x_n\}. Then

• 1st-order differences:

\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}

• 2nd-order differences:

\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}

• 3rd-order differences:

\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}

• 4th-order differences:

\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}

From here I made the assumption that \Delta^4\{x_n\} is the constant sequence {15, 15, 15, …}. This implies \Delta^3\{x_n\} forms an arithmetic/linear sequence, which implies \Delta^2\{x_n\} forms a quadratic sequence, and so on up \{x_n\} forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.

5 0
2 years ago
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