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Rama09 [41]
3 years ago
5

BRAINLIEST AND 21 POINTS NEED HELP ASAP

Mathematics
1 answer:
Irina-Kira [14]3 years ago
8 0

Answer:

I'm notttt sureeeeee I think its C i don't know,

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The answer is 2x because of the distance formula
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3 years ago
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A candy store owner wants to mix some candy costing $1.25 a pound
maria [59]

The candy store owner should use 37.5 pounds of the candy costing $1.25 a pound.

Given:

  • Candy costing $1.25 a pound is to be mixed with candy costing $1.45 a pound
  • The resulting mixture should be 50 pounds of candy
  • The resulting mixture should cost $1.30 a pound

To find: The amount of candy costing $1.25 a pound that should be mixed

Let us assume that the resulting mixture should be made by mixing 'x' pounds of candy costing $1.25 a pound.

Since the total weight of the resulting mixture should be 50 pounds, 'x' pounds of candy costing $1.25 a pound should be mixed with '50-x' pounds of candy costing $1.45 a pound.

Then, the resulting mixture contains 'x' pounds of candy costing $1.25 a pound and '50-x' pounds of candy costing $1.45 a pound.

Accordingly, the total cost of the resulting mixture is 1.25x+1.45(50-x)

However, the resulting mixture should be 50 pounds and should cost $1.30 a pound. Accordingly, the total cost of the resulting mixture is 1.30 \times 50

Equating the total cost of the resulting mixture obtained in two ways, we get,

1.25x+1.45(50-x)=1.30 \times 50

1.25x+72.5-1.45x=65

0.2x=7.5

x=\frac{7.5}{0.2}

x=37.5

This implies that the resulting mixture should be made by mixing 37.5 pounds of candy costing $1.25 a pound.

Learn more about cost of mixtures here:

brainly.com/question/17109505

4 0
3 years ago
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MATH QUESTION, PLEASE HELP !!!<br> (will mark branliest )
Aleksandr [31]

Answer:

I am not certain if its right

Step-by-step explanation:

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3 years ago
In a pizza store, there are six possible toppings. On a large pizza, you can have 3 toppings. How many combinations of pizza top
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Answer:

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Step-by-step explanation:

The questions asks about Combinations of Pizza toppings, so by employing the Combination Formula:

C(n, k) = \frac{n!}{k!(n-k)!}

C(6, 3) = \frac{6!}{3! \cdot 3!} = \frac{6 \cdot 5 \cdot 4 \cdot 3 \cdot 2}{3 \cdot 2 \cdot 3 \cdot 2} = 20

8 0
3 years ago
Zeke had 10 marbles in the beginning of the game and he had 7 at the end of the game. What was the percent loss?
zloy xaker [14]
The answer is 30%. It would be like 70% is what you have left of the 100.
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