I think you can find it graphically by points through a table you create like:
let x = 0, and find the value of y
for example for the first equation when we let x = 0 you find y = 6 and be in the form of (0,6) then draw them or you can let x = -2 or -3 , etc as you like
to be more accurate you can find 3 pionts and start graphing them
these two equations are straight lines and they will intersect in a point
Answer:
D
Step-by-step explanation:
without knowing anything about the background of the function and what it is used for, I give it the max. possible domain (the set or interval of all possible input values).
and so,
Defined for all m >= 0 and n >= 0.
there is no information provided that would eliminate m = 0 or n = 0.
Answer:
What's the question? Please post the full question
Answer:
C ) 10/m⁵
Step-by-step explanation:
In this question, we have to find the product of two terms
First term = 5 m⁻²
Second term = 2 m⁻³
Product of both terms = (5 m⁻²) · (2 m⁻³)
The simple way of calculating product of these two term which involves constants as well as variable is that we multiply the constants together:
5·2 = 10
And we multiply the variables. According to the rules of multiplication, when 2 same constants or variables are multiplied, we can just add their powers to get the result.
(m⁻²) · (m⁻³) = m⁻²⁻³ = m⁻⁵
The product of both terms can be written as:
(product of constants)(product of variables) = (10)(m⁻⁵) = 10/m⁵
So the correct option is C
