Question

Which expression is equivalent to the product of p+7/3 and 6/p , where p is not equal to 0?

Answer 1

Answer:

$\frac{(6p+14)}{p}$

Step-by-step explanation:

$(p+\frac{7}{3})(\frac{6}{p})$

Making denominator same in first bracket we get

$(\frac{3p+7}{3})(\frac{6}{p})$

$(\frac{(3p+7)*6}{3*p})$

Dividing 6 by 3 we get 2

$(\frac{(3p+7)*2}{p})$

using distributive law

$(\frac{6p+14}{p})$

Hence this is our answer

Answer 2

Answer:

Option d. 2p +  $\frac{14}{p}$

Step-by-step explanation:

We have to find the expression equivalent to the product of ( P + $\frac{7}{3}$) and (  $\frac{6}{p}$ ) where p ≠ 0

( p +  $\frac{7}{3}$ ) × (  $\frac{6}{p}$ )

= p (  $\frac{6}{p}$ ) + (  $\frac{7}{3}$ ) ( $\frac{6}{p}$ ) [distributive law]

= 6 + ( $\frac{14}{p}$ )

=  $\frac{(6p+14)}{p}$

Therefore, option D is the answer.