Question

Find two numbers who have a sum of 21 and a product of 104.

Answer 1

The  two numbers are 8 and 13 and the system of equations are x + y = 21 and xy = 104

System of equations

Let the two unknown numbers be x and y

If the sum of the numbers is 21, hence;

x + y = 21

x = 21 - y

If the product is 104, then;

xy = 104
(21-y)y = 104

21y - y^2 = 104
y^2-21y + 104 = 0

Factorize the result

y^2-8y - 13y+ 104 = 0
y(y-8) - 13()y-8) = 0
y = 13 and 8

Hence the two numbers are 8 and 13 and the system of equations are x + y = 21 and xy = 104

Learn more on system of equation here:  brainly.com/question/847634