Answer:
The probability that the town has 30 or fewer residents with the illness = 0.00052.
Step-by-step explanation:
So, we have the following set of data or information or parameters given from the question above and they are; the number of people living in that particular society/community/town = 74,000 residents and the proportion of people that the diseases affected = .000215.
The first step to do is to determine the expected number of people with disease. Thus, the expected number of people with disease = 74,000 × .000215 = 15.91.
Hence, the probability that the town has 30 or fewer residents with the illness = 1.23 × 10^-7 × 15.91^30/ 2.65253 × 10^-32 = 0.00052.
Note the formula used in the calculating the probability that the town has 30 or fewer residents with the illness = e^-λ × λ^x/ x!
Answer:
Your answer would be c 18=2x
Step-by-step explanation:
Because you done did 3x=9 which you now have to do the other end of the problem.
Answer: g(4)= -60
Step-by-step explanation:
You just plug in 4 into the equation
g(4)= 2√4 - (4)³
g(4)= 2√4 - (4)³
g(4)= 2·2 - (64)
g(4)= 4 - 64
g(4)= -60
