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Roger just ran 5 laps. He is at 20% of his goal.

Vladimir79 [104]

Answer: 20 laps

Step-by-step explanation:

Given

Roger just ran 5 laps and completes 20% of his goal

Suppose his goal is x laps

So, 20% of x must be equal to 5

$\Rightarrow 20\%\times x=5\\\Rightarrow 0.2x=5\\\\\Rightarrow x=\dfrac{5}{0.2}\\\\\Rightarrow x=\dfrac{50}{2}\\\\\Rightarrow x=25\ \text{laps}$

So, he needs 20 more laps to complete his goal.

3 0

3 years ago

Plz help will make brainliest!!!!!

kirza4 [7]

Answer:

x = 7.5

Step-by-step explanation:

Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. Do the opposite of PEMDAS.

PEMDAS is the order of operation, and equals:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

First, subtract 2x from both sides of the equation:

10x (-2x) = 2x (-2x) + 60

10x - 2x = 60

8x = 60

Next, isolate the variable, x. Divide 8 from both sides of the equation:

(8x)/8 = (60)/8

x = 60/8

x = 7.5

x = 7.5 is your answer.

~

4 0

3 years ago

The diameters of bearings used in an aircraft landing gear assembly have a standard deviation of ???? = 0.0020 cm. A random samp

vovikov84 [41]

Answer:

(a) We conclude after testing that mean diameter is 8.2500 cm.

(b) P-value of test = 2 x 0.0005% = 1 x $10^{-5}$ .

(c) 95% confidence interval on the mean diameter = [8.2525 , 8.2545]

Step-by-step explanation:

We are given with the population standard deviation, $\sigma$ = 0.0020 cm

Sample Mean, Xbar = 8.2535 cm and Sample size, n = 15

(a) Let Null Hypothesis, $H_0$ : Mean Diameter, $\mu$ = 8.2500 cm

Alternate Hypothesis, $H_1$ : Mean Diameter, $\mu$ $\neq$ 8.2500 cm{Given two sided}

So, Test Statistics for testing this hypothesis is given by;

$\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ follows Standard Normal distribution

After putting each value, Test Statistics = $\frac{8.2535-8.2500}{\frac{0.0020}{\sqrt{15} } }$ = 6.778

Now we are given with the level of significance of 5% and at this level of significance our z score has a value of 1.96 as it is two sided alternative.

<em>Since our test statistics does not lie in the rejection region{value smaller than 1.96} as 6.778>1.96 so we have sufficient evidence to accept null hypothesis and conclude that the mean diameter is 8.2500 cm.</em>

(b) P-value is the exact % where test statistics lie.

For calculating P-value , our test statistics has a value of 6.778

So, P(Z > 6.778) = Since in the Z table the highest value for test statistics is given as 4.4172 and our test statistics has value higher than this so we conclude that P - value is smaller than 2 x 0.0005% { Here 2 is multiplied with the % value of 4.4172 because of two sided alternative hypothesis}

Hence P-value of test = 2 x 0.0005% = 1 x $10^{-5}$ .

(c) For constructing Two-sided confidence interval we know that:

Probability(-1.96 < N(0,1) < 1.96) = 0.95 { This indicates that at 5% level of significance our Z score will lie between area of -1.96 to 1.96.

P(-1.96 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96\frac{\sigma}{\sqrt{n} }$ < $Xbar - \mu$ < $1.96\frac{\sigma}{\sqrt{n} }$ ) = 0.95

P( $-Xbar-1.96\frac{\sigma}{\sqrt{n} }$ < $-\mu$ < $1.96\frac{\sigma}{\sqrt{n} }-Xbar$ ) = 0.95

P( $Xbar-1.96\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $Xbar+1.96\frac{\sigma}{\sqrt{n} }$ ) = 0.95

So, 95% confidence interval for $\mu$ = [ $Xbar-1.96\frac{\sigma}{\sqrt{n} }$ , $Xbar+1.96\frac{\sigma}{\sqrt{n} }$ ]

= [ $8.2535-1.96\frac{0.0020}{\sqrt{15} }$ , $8.2535+1.96\frac{0.0020}{\sqrt{15} }$ ]

= [8.2525 , 8.2545]

Here $\mu$ = mean diameter.

Therefore, 95% two-sided confidence interval on the mean diameter

= [8.2525 , 8.2545] .

6 0

2 years ago

Read 2 more answers

1. The rent of a condo unit was ₱1,200.00 for one night, to be shared equally by a group of female friends, who will be having t

zhuklara [117]

Answer:

6 girls were there are first

Step-by-step explanation:

use trial and error. divide 1200 by a random number like 10, and see how much they each had to pay. If we guessed 10, then each girl would hypothetically pay 120 pounds. If four girls left, then 1200/6 would be 200 pounds. there was only a 60 pound increase here, not a 400 pound one.

I checked 1200/6 which equals 200 pounds per girl. If 4 girls left, then it would be 600 pounds for the 2 remaining girls. the rent increased from 200 to 600 which is a 400 pound increase.

4 0

2 years ago

Guys so it says pick which one is true and!!! I can’t really find out now there is four more left thank you to the people who ar

Masja [62]

Answer:

Your answer is

B. C. And. E

Hope it will help :)❤

6 0

2 years ago