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3 years ago

What is 2x+4x7x-19x+7y+9x

Mathematics

2 answers:

lutik1710 [3]3 years ago

8 0

Answer:

if you simplify it is =4x^8−8x+7y

if i can get brainliest that would be great

Combine Like Terms:

=2x+4x^8+−19x+7y+9x

=(4x^8)+(2x+−19x+9x)+(7y)

=4x^8+−8x+7y

s2008m [1.1K]3 years ago

6 0

Answer: do the math, 39x

Step-by-step explanation:2+4=6 times 7=42-19=23+7=30+9=39x

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Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

$k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2$

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Step-by-step explanation:

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UNO [17]

I = PRT

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720 = 90(t)
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I am not sure if it is terms of months or years but 8 is the answer. hope it helps :)

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