Answer:
Sol: In this question, firstly we have to make the first bracket as a complete square of the second bracket. This we can by adding 2.x.1/x which is equivalent to 2. Then the equation becomes:
6(x2 + 1/x2 +2) – 5(x + 1/x) = 50 { 38 + 6*2)
⇒ 6(x2 + 1/x2 +2) – 5(x + 1/x) – 50 = 0
Now put x + 1/x = y
⇒ 6y2 -5y -50 = 0
⇒ (2y +5)(3y-10)= 0
⇒ y=-5/2 or 10/3
As x is positive therefore, x + 1/x =10/3
On solving further you will get as x=3 or 1/3
The required value is 8
How can we find value?
We will find the value by putting the value of w in the given function to get the required value.
We can find the value of given function foe w=2 as shown below:
Given, function is 2w+w^3-1/2w^2
Let A=2w+w^3-1/2w^2
for w=2
A=2(2)+(2)^3-1/2(2)^2
= 2+8-1/2(4)
=2+8-2
=8
Hence, the required value is 8.
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Answer
Buy 2, get 2 free and/or 1/2 off
Step-by-step explanation:
OK, lets say that the tire price was 15. (l)= 15+15=30 (ll)= 15/45%= 33.33x4=133.32 (lll)= 15/2=7.5 7.5x4=30
The percentage of the radioactive isotope left is 25.0000%.
<h3>What is the half life?</h3>
The half life of a radioactive isotope is the time that will elapse before only half of the number of original isotopes will remain.
Now;
We are told that;
Half life (t1/2) = 55 days
Time taken (t) = 115 days
Ratio of isotope remaining = N/No
Thus;
N/No = (1/2)^t/t1/2
N/No = (1/2)^115/55
N/No = (1/2)^2
N/No =1/4
Hence, the percentage = 1/4 * 100/1 = 25.0000%
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