10+8=5x+3x
18=8x
X=2,25
Hope it’s right
Let us assume then that the center is the origin. If the major axis is 18, then a = 9 and a^2=81. If the minor axis is 16, then b = 8 and b^2=64. Now you can write the equation. Remember that this ellipse is vertical and so a^2 goes under y^2
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Find area of the border :
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Area of the room = 22 x 25 = 550 ft²
Area of the rug = 238 ft²
Area of the border = 550 - 238 = 312 ft²
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Define y:
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Let the width be y.
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Find area of the border in term of y :
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The area of the border = 22y x 2 + 25y x 2 - 4y² = 94y - 4y²
*We need to take away 4y² because the 4 corners will be overlap twice if we don't.
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Solve y :
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94y - 4y² = 312
4y² - 94y + 312 = 0
2y² - 47y + 156 = 0
<span>(y - 4)(2y - 39) = 0
</span>y = 4 or y = 19.5
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Answer: The border can be 4 ft or 19.5 ft
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-47 is the absolute value
