C. velocity includes the direction of travel whereas speed does not.
We know they combine to 2,977 grams. The puppies weight the same
Let’s make puppy = x
Basket weight = 1,077
8x + 1077 = 2977
8x = 1900, x = 237.5 grams
It would be around 250 grams
Answer:
This is called a mid segment theorem in which the al ine segment (DE) joining the midpoints of two sides of a triangle is parallel to the third side.
Step-by-step explanation:
Suppose we have a triangle ABC. Then the midpoints can be located as D, E and F. If we join D , E and F another triangle is formed.
From the figure we can see that
AE≅ CE
AD≅DB
BF≅CF
BECAUSE all the given points are the midpoints which divide the lines into two equal halves.
If we increase the line DE to a point L we find out that DL is parallel to BC i.e. it does not meet at any point with BC. ( the two lines do not meet)
(1)
If we join C with L we find out that the the line DE is half in length to the line BC.
AS
AE= CE (midpoints dividing into equal line segements.)
LE= DE
Triangle CEL= Triangle DEF
so
DL= BC
But DE = 1/2 DL
therefore
DE= 1/2 BC (2)
Therefore from 1 and 2 we find that a line segment (DE) joining the midpoints of two sides of a triangle is parallel to the third side
Answer:
120
Step-by-step explanation:
Answer:
probability of selecting the square is 63.7% approximately
Step-by-step explanation:
First of all, the probability of the point of choice is within the red square can be obtained with this formula
probability = expected outcome / total number of possible outcomes
In this case, we are not dealing with discrete values which can be counted. instead, we are dealing with areas.
We are to go about this problem by finding the area of the internal square and dividing it by the area of the circle.
Area of the square
Area of the square =
where length =
Area =
Area of the circle
Area of the circle =
area of circle =
Probablity of selecting the square =
32/50.26 = 0.6366
To express this as a percentage, we multiply our answer by 100.
This will give us 0.6366 X 100 = 63.7% approximately