Answer:
Step-by-step explanation:
Formula to be used is N=N0e^(kt)
N0 - amount of bacteria at time 0, which is 10g
t=2, 30g
30 = 10*e^(k*2)
3 = e^(2k)
2k = ln3
k = 0.5ln3
At t=6:
N = 10*e^(0.5ln3*6)
N = 10e^(3ln3)
N = 10e^ln27
N = 10*27 =270
So the amount of bacteria at t=6 is 270
Answer:
Step-by-step explanation:
.05
Well, I do not know if you mean 93x = 7 or 9^3x = 7.
So, I will provide the solution for both cases.
In case of 93x = 7:
This case is simple, all you have to do is isolate the x. You need to get rid of the coefficient which is 93. You can simply do this by dividing both sides of the equation by 93 as follows:
93x = 7
93x / 93 = 7/93
x = 7/93
In case of 9^3x = 7:
Now, we need to get rid of the power. The only function that can do this is the log function.
So, we will start by taking log base 10 for both sides of the equation as follows:
9^3x = 7
log(9^3x) = log(7)
This will give:
3x * log(9) = log(7)
Now, the final step is to isolate the x as we did before. To do this, we will need to get rid of 3log(9). This can be done by dividing both sides of the equation by 3log(9) as follows:
3x * log(9) / 3log(9) = log(7) / 3log(9)
This will give us:
x = log(7) / 3log(9) = 0.2952
Hope this helps :)
Answer:
67-100
Step-by-step explanation:
This is the answer because the . is ones the 6 is tens and the 7 is the hundreds
Answer:
All real numbers less than or equal to 3
Step-by-step explanation:
we have
Solve for y
Subtract 2y both sides
The solution is the interval ------> (-∞,3]
All real numbers less than or equal to 3
In a number line the solution is the shaded area down of y=3 (close circle)
see the attached figure
