The amount of bacteria in a petri dish increases at a rate proportional to the amount present. At time t=0, the amount of bacter ia in the dish is 10 grams. At time t=2, the amount of bacteria in the dish is 30 grams. What is the amount of bacteria in the dish at time t=6 ?
1 answer:
Answer:
Step-by-step explanation:
Formula to be used is N=N0e^(kt)
N0 - amount of bacteria at time 0, which is 10g
t=2, 30g
30 = 10*e^(k*2)
3 = e^(2k)
2k = ln3
k = 0.5ln3
At t=6:
N = 10*e^(0.5ln3*6)
N = 10e^(3ln3)
N = 10e^ln27
N = 10*27 =270
So the amount of bacteria at t=6 is 270
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Step-by-step explanation:
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