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mr_godi [17]
3 years ago
7

Solve the inequality 3y <= 2y + 3

Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

y\leq 3

All real numbers less than or equal to 3

Step-by-step explanation:

we have

3y\leq 2y+3

Solve for y

Subtract 2y both sides

3y-2y\leq 2y+3-2y

y\leq 3

The solution is the interval ------> (-∞,3]

All real numbers less than or equal to 3

In a number line the solution is the shaded area down of y=3 (close circle)

see the attached figure

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Answer:

Step-by-step explanation:

Using the section formula, if a point (x,y) divides the line joining the points (x  

1

​

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,y  

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​

) in the ratio m:n, then  

(x,y)=(  

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​

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​

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The vertices of the triangle are given to be (x  

1

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,y  

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​

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​

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2

​

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​

,y  

3

​

). Let these vertices be A,B and C respectively.  

Then the coordinates of the point P that divides AB in l:k will be

(  

l+k

lx  

2

​

+kx  

1

​

 

​

,  

l+k

ly  

2

​

+ky  

1

​

 

​

)

The coordinates of point which divides PC in m:k+l will be  

⎩

⎪

⎪

⎪

⎨

⎪

⎪

⎪

⎧

​

 

m+k+l

mx  

3

​

+(k+l)  

(l+k)

lx  

2

​

+kx  

1

​

 

​

 

​

,  

m+k+l

my  

3

​

+(k+l)  

(l+k)

ly  

2

​

+ky  

1

​

 

​

 

​

 

⎭

⎪

⎪

⎪

⎬

⎪

⎪

⎪

⎫

​

 

⇒(  

m+k+l

kx  

1

​

+lx  

2

​

+mx  

3

​

 

​

,  

m+k+l

ky  

1

​

+ly  

2

​

+my  

3

​

 

​

)

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