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mr_godi [17]
3 years ago
7

Solve the inequality 3y <= 2y + 3

Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

y\leq 3

All real numbers less than or equal to 3

Step-by-step explanation:

we have

3y\leq 2y+3

Solve for y

Subtract 2y both sides

3y-2y\leq 2y+3-2y

y\leq 3

The solution is the interval ------> (-∞,3]

All real numbers less than or equal to 3

In a number line the solution is the shaded area down of y=3 (close circle)

see the attached figure

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Rick bought a car for $17,500. Each year, the car's value decreases by 20%. At this rate, what can Rick expect the value of his
Arada [10]

Answer:

His car would be worth $15,502.24

Step-by-step explanation:

20% of 17,500 is 350. 350 x 6 = 2,100. 17,500 - 2,100 = 15,400. But that is not an answer choice so be go to  the closest number which is $15,502.24

5 0
2 years ago
Michael works in a supper market.he is paid 10.80 per hour .what is Michels overt time pay rate
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2 years ago
Need help asap please !!!!!!!!
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5 0
3 years ago
Read 2 more answers
What is the distance in the standard (x, y) coordinate<br> plane between the points (2,3) and (5,5)?
Naddik [55]
<h3>The distance between the points (2,3) and (5,5) is 3.6 units</h3>

<em><u>Solution:</u></em>

<em><u>Distance between two points is given by:</u></em>

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

We have to find the distance in the standard (x, y) coordinate  plane between the points (2,3) and (5,5)

From given,

(x_1, y_1) = (2, 3)\\\\(x_2, y_2) = (5, 5)

Substituting the values we get,

d = \sqrt{(5-2)^2 + (5-3)^2}\\\\Simplify\\\\d = \sqrt{3^2 + 2^2}\\\\d = \sqrt{9+4}\\\\d = \sqrt{13}\\\\In\ decimal\ form\\\\d = 3.605 \approx 3.6

Thus distance between the points (2,3) and (5,5) is 3.6 units

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3 years ago
What's 1/10 at four in the number 42,000
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3 years ago
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