9514 1404 393
Answer:
? = √87 ≈ 9.33
Step-by-step explanation:
The square of the hypotenuse (h) of the small triangle is the sum of the squares of its legs.
h^2 = 5^2 + 12^2 = 25 +144 = 169
The square of the hypotenuse of the large triangle is also the sum of the squares of its legs.
h^2 +?^2 = 16^2
169 +?^2 = 256
?^2 = 256 -169 = 87
Taking the square root, we find the missing leg length to be ...
? = √87 ≈ 9.33
Answer:
first option
Step-by-step explanation:
Using the sine/ cosine ratios in the right triangle and the exact values
sin30° = , cos30° =
sin30° = = = ( cross- multiply )
2x = 32 ( divide both sides by 2 )
x = 16
----------------------------------------------------------
cos30° = = = ( cross- multiply )
2y = 32 ( divide both sides by 2 )
y = 16
La formula para sacar la pendiente:
Y2-Y1/X2-X1
Respuesta:
Y2-Y1/X2-X1= -2-(-10)/-1-(-1)
= -2+10/ -1+1= 8
R=8
Espero que te sirva
Answer:
Pick up point is 1.43 km from the school and drop point is 3.57 km from the school ( to the nearest hundredth).
Step-by-step explanation:
School <----------- 5 km ---------------> Home
_______ P _______ D _______
x km y km 5-x-y km
_______
y
_________________
5-x km
D is the point where Peter drops off N and P is the pick point x km from the school where Peter picks up R. He travels back y km to pick up R.
We work in times:
Time = distance / speed
The time that R walks from the school to point P is the same as Peter travels the distance (x + 2y) km, so we have
x/5 = (x + 2y)/20
20x = 5x + 10y
15x - 10y = 0 A
The time that N walks home equals the time that Peter travels y + 5 - x km.
So (y + 5 - x)/20 = (5 - x - y)/5
5y + 25 - 5x = 100 - 20x - 20y
15x + 25y = 75
3x + 5y = 15 B
Solving equation A and B
15x - 10y = 0
3x + 5y = 15
Multiply the second equation by 2:
6x + 10y = 30
Adding this to the first equation
21x = 30
x = 30/21 = 1.4285
So 3(1.4285) + 5y = 15
y = 2.1428
Pick up x = 1.43 km
and the drop is 1.43 + 2.14 = 3,57 km from the school
3^2-1/2+1=
9-1/3=
8/3=
2 2/3 so A.