Question

Special Right Triangles

Answer 1

Answer:

first option

Step-by-step explanation:

Using the sine/ cosine ratios in the right triangle and the exact values

sin30° = $\frac{1}{2}$ , cos30° = $\frac{\sqrt{3} }{2}$

sin30° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{32}$ = $\frac{1}{2}$ ( cross- multiply )

2x = 32 ( divide both sides by 2 )

x = 16

----------------------------------------------------------

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{y}{32}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2y = 32$\sqrt{3}$ ( divide both sides by 2 )

y = 16$\sqrt{3}$